2x^2-16x-218=0

Solution for 2x^2-16x-218=0 equation:

2x^2-16x-218=0

a = 2; b = -16; c = -218;
Δ = b2-4ac
Δ = -162-4·2·(-218)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20\sqrt{5}}{2*2}=\frac{16-20\sqrt{5}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20\sqrt{5}}{2*2}=\frac{16+20\sqrt{5}}{4}
$